P384
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Rudin-Shapiro Sequence

ℹ️Published on Sunday, 13th May 2012, 02:00 am; Solved by 366;
Difficulty rating: 65%

Define the sequence a(n) as the number of adjacent pairs of ones in the binary expansion of n (possibly overlapping).
E.g.: a(5)=a(1012)=0, a(6)=a(1102)=1, a(7)=a(1112)=2.

Define the sequence b(n)=(1)a(n).
This sequence is called the Rudin-Shapiro sequence.

Also consider the summatory sequence of b(n): s(n)=i=0nb(i).

The first couple of values of these sequences are:

n 0 1 2 3 4 5 6 7
a(n) 0 0 0 1 0 0 1 2
b(n) 1 1 1 1 1 1 1 1
s(n) 1 2 3 2 3 4 3 4

The sequence s(n) has the remarkable property that all elements are positive and every positive integer k occurs exactly k times.

Define g(t,c), with 1ct, as the index in s(n) for which t occurs for the c'th time in s(n).
E.g.: g(3,3)=6, g(4,2)=7 and g(54321,12345)=1220847710.

Let F(n) be the Fibonacci sequence defined by:
F(0)=F(1)=1 and
F(n)=F(n1)+F(n2) for n>1.

Define GF(t)=g(F(t),F(t1)).

Find GF(t) for 2t45.



Soluzione

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